[{"createTime":1735734952000,"id":1,"img":"hwy_ms_500_252.jpeg","link":"https://activity.huaweicloud.com/cps.html?fromacct=261f35b6-af54-4511-a2ca-910fa15905d1&utm_source=V1g3MDY4NTY=&utm_medium=cps&utm_campaign=201905","name":"华为云秒杀","status":9,"txt":"华为云38元秒杀","type":1,"updateTime":1735747411000,"userId":3},{"createTime":1736173885000,"id":2,"img":"txy_480_300.png","link":"https://cloud.tencent.com/act/cps/redirect?redirect=1077&cps_key=edb15096bfff75effaaa8c8bb66138bd&from=console","name":"腾讯云秒杀","status":9,"txt":"腾讯云限量秒杀","type":1,"updateTime":1736173885000,"userId":3},{"createTime":1736177492000,"id":3,"img":"aly_251_140.png","link":"https://www.aliyun.com/minisite/goods?userCode=pwp8kmv3","memo":"","name":"阿里云","status":9,"txt":"阿里云2折起","type":1,"updateTime":1736177492000,"userId":3},{"createTime":1735660800000,"id":4,"img":"vultr_560_300.png","link":"https://www.vultr.com/?ref=9603742-8H","name":"Vultr","status":9,"txt":"Vultr送$100","type":1,"updateTime":1735660800000,"userId":3},{"createTime":1735660800000,"id":5,"img":"jdy_663_320.jpg","link":"https://3.cn/2ay1-e5t","name":"京东云","status":9,"txt":"京东云特惠专区","type":1,"updateTime":1735660800000,"userId":3},{"createTime":1735660800000,"id":6,"img":"new_ads.png","link":"https://www.iodraw.com/ads","name":"发布广告","status":9,"txt":"发布广告","type":1,"updateTime":1735660800000,"userId":3},{"createTime":1735660800000,"id":7,"img":"yun_910_50.png","link":"https://activity.huaweicloud.com/discount_area_v5/index.html?fromacct=261f35b6-af54-4511-a2ca-910fa15905d1&utm_source=aXhpYW95YW5nOA===&utm_medium=cps&utm_campaign=201905","name":"底部","status":9,"txt":"高性能云服务器2折起","type":2,"updateTime":1735660800000,"userId":3}]
一、支持连续按：
u8 KEY_Scan(void)
{
if(KEY按下）
{
delay_ms(10)；//延时10-20ms，防抖。
if(KEY确实按下)
{
return KEY_Value；
}
return 无效值；
}
}
流程图如下
这种思路很简单，就是通过一直扫描，然后判断按键是否按下，如果按下就返回有效值，否则返回无效值。所以这种方式支持按键连续按。
二、不支持连续按：
u8KEY_Scan(void)
{
static u8 key_up=1;
if（key_up&& KEY按下）
{
delay_ms(10);//延时，防抖
key_up=0;//标记这次key已经按下
if(KEY确实按下)
{
return KEY_VALUE;
}
}else if(KEY没有按下) key_up=1;
return 没有按下
}
这种思路也比较容易理解，那就是通过静态局部变量的key_up的引入，key_up的作用就是记录上一次按键的状态，当上一次key_up=1的时候就代表按键处于没有按下的状态，而如果key_up的值为0，则表明按键已经按下，这次函数就不会进入确认按键是否按下的语句。总结一下就是如果上次按键没有按下，而现在检测到按键按下，就把key_up赋0，并且返回判断过的值。否则就赋1.
三、通过一个形参，把两个函数和为一个函数
u8 KEY_Scan(u8mode)
{
static u8 key_up=1;
if(mode==1) key_up=1;//支持连续按
if（key_up&& KEY按下）
{
delay_ms(10);//延时，防抖
key_up=0;//标记这次key已经按下
if(KEY确实按下)
{
return KEY_VALUE;
}
}else if(KEY没有按下) key_up=1;
return 没有按下
}
如过mode为1，则支持连续按，否则不支持连续按。
