[{"createTime":1735734952000,"id":1,"img":"hwy_ms_500_252.jpeg","link":"https://activity.huaweicloud.com/cps.html?fromacct=261f35b6-af54-4511-a2ca-910fa15905d1&utm_source=V1g3MDY4NTY=&utm_medium=cps&utm_campaign=201905","name":"华为云秒杀","status":9,"txt":"华为云38元秒杀","type":1,"updateTime":1735747411000,"userId":3},{"createTime":1736173885000,"id":2,"img":"txy_480_300.png","link":"https://cloud.tencent.com/act/cps/redirect?redirect=1077&cps_key=edb15096bfff75effaaa8c8bb66138bd&from=console","name":"腾讯云秒杀","status":9,"txt":"腾讯云限量秒杀","type":1,"updateTime":1736173885000,"userId":3},{"createTime":1736177492000,"id":3,"img":"aly_251_140.png","link":"https://www.aliyun.com/minisite/goods?userCode=pwp8kmv3","memo":"","name":"阿里云","status":9,"txt":"阿里云2折起","type":1,"updateTime":1736177492000,"userId":3},{"createTime":1735660800000,"id":4,"img":"vultr_560_300.png","link":"https://www.vultr.com/?ref=9603742-8H","name":"Vultr","status":9,"txt":"Vultr送$100","type":1,"updateTime":1735660800000,"userId":3},{"createTime":1735660800000,"id":5,"img":"jdy_663_320.jpg","link":"https://3.cn/2ay1-e5t","name":"京东云","status":9,"txt":"京东云特惠专区","type":1,"updateTime":1735660800000,"userId":3},{"createTime":1735660800000,"id":6,"img":"new_ads.png","link":"https://www.iodraw.com/ads","name":"发布广告","status":9,"txt":"发布广告","type":1,"updateTime":1735660800000,"userId":3},{"createTime":1735660800000,"id":7,"img":"yun_910_50.png","link":"https://activity.huaweicloud.com/discount_area_v5/index.html?fromacct=261f35b6-af54-4511-a2ca-910fa15905d1&utm_source=aXhpYW95YW5nOA===&utm_medium=cps&utm_campaign=201905","name":"底部","status":9,"txt":"高性能云服务器2折起","type":2,"updateTime":1735660800000,"userId":3}]
1.例子
例如，求（319，377）：
∵ 319÷377=0（余319）
∴（319，377）=（377，319）；
∵ 377÷319=1（余58）
∴（377，319）=（319，58）；
∵ 319÷58=5（余29）
∴ （319，58）=（58，29）；
∵ 58÷29=2（余0）
∴ （58，29）= 29；
∴ （319，377）=29
由规律知： 余数的值是呆在下一轮除数的位置，原本除数的位置是下一轮被除数的位置
2.解题思路
辗转相除法 用来求最大公约数 主要抓住两个tip，伙计们
函数声明一波 int gcd (int a,int b);
（1）首先呢 第一个数a要大于第二个数!!!
若a<b,则要进行交换
ppl如下：
if(a<b)//正确的位置关系应该是：大值在第一个位置， 小值在第二个位置 { int temp;//中间变量 temp=a;//将**小值**赋给中间变量
a=b;//**大值**赋给a所在的位置 b=temp;//将**小值**赋给b所在的位置 }
(2)辗转相除法的过程ppl
while(b!=0) { int temp=a%b; a=b;//将除数的值赋给下一轮被除数的位置 b=temp;//将余数的值赋给下一轮b的位置
3.代码实习
import java.util.Scanner; public class Main31 { public static void main(String[
] args) { // TODO Auto-generated method stub Scanner sc=new Scanner(System.in);
int a,b,t=1; a=sc.nextInt(); b=sc.nextInt(); do { int temp=a%b;//求余数 a=b;
//将除数的值赋给下一轮被除数的位置 b=temp;//将余数的值赋给下一轮除数的位置 }while(b!=0); System.out.println(a);
} }
