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今天使用列表写入字典时,发现列表内容居然全是相同的字典,并且还是最后一个写入的字典
例:
a=[] b={ "name":" " } for i in range(4): b["name"]=i a.append(b) print(a)
运行结果为:
[{'name': 3}, {'name': 3}, {'name': 3}, {'name': 3}]
? ? ？
里面不是应该是０，１，２，３吗，为什么全是３呢，找了一些资料发现问题了，原来列表用append为列表添加数据的时候并不是将完整的字典数据都写入的列表当中，而是写入字典数据所在地址，而以上这种方式修改的是该内存地址下的数据，这就导致列表存储的全是同一个字典的地址，最后输出时从地址调出的就是最后的字典了
解决办法
可以使用ｃｏｐｙ（）解决这一问题
a=[] b={ "name":" " } for i in range(4): b["name"]=i a.append(b.copy()) print(a
)
输出：
[{'name': 0}, {'name': 1}, {'name': 2}, {'name': 3}]
完美解决！
