一道SQL题

有个搞数仓的朋友不知道从哪儿弄了个题。。。
做了做体验了一下。。。
记录记录。

<>分析

要保证每天都要做新题
5天必须都做题，不然GG
最后一天必须做新题，如果最后一天做新题了，前面那几天没做新题，做的是老题

最后一天，如果没做题会被踢出
最后一天做的题，不是新题记录0，当求和之后为0，说明没有新题，那就踢出
如果是最后一天做了新题，第四天没做新题

下面的问题需要处理，

用户a，前四天（1，2，3）
第一天：1，2，3
第二天：1，2，3
第三天：1，2，3
第四天：1，2，3

第五天：1，2，3，4

保证最后一天做新题的案例：
SELECT info.user_id FROM ( SELECT two.user_id, sum( IF ( two.question_id IN (
SELECT DISTINCT one.question_id FROM log_table AS one WHERE one.date between
"2022-09-19" and "2022-09-22" AND one.user_id = two.user_id ), 0, 1 )) AS num
FROM log_table AS two WHERE two.date = "2022-09-23" GROUP BY two.user_id ) info
WHERE info.num >0
<>补充完善
select * from (SELECT info.user_id FROM ( SELECT two.user_id, sum( IF (
two.question_id IN ( SELECT DISTINCT one.question_id FROM log_table AS one
WHERE one.date between "2022-09-19" and "2022-09-22" AND one.user_id =
two.user_id ), 0, 1 )) AS num FROM log_table AS two WHERE two.date =
"2022-09-23" GROUP BY two.user_id ) info WHERE info.num >0) as d5 left join
(SELECT info.user_id FROM ( SELECT two.user_id, sum( IF ( two.question_id IN (
SELECT DISTINCT one.question_id FROM log_table AS one WHERE one.date between
"2022-09-19" and "2022-09-21" AND one.user_id = two.user_id ), 0, 1 )) AS num
FROM log_table AS two WHERE two.date = "2022-09-22" GROUP BY two.user_id ) info
WHERE info.num >0) as d4 on d5.user_id = d4.user_id left join (SELECT
info.user_id FROM ( SELECT two.user_id, sum( IF ( two.question_id IN ( SELECT
DISTINCT one.question_id FROM log_table AS one WHERE one.date between
"2022-09-19" and "2022-09-20" AND one.user_id = two.user_id ), 0, 1 )) AS num
FROM log_table AS two WHERE two.date = "2022-09-21" GROUP BY two.user_id ) info
WHERE info.num >0) as d3 on d5.user_id = d3.user_id left join (SELECT
info.user_id FROM ( SELECT two.user_id, sum( IF ( two.question_id IN ( SELECT
DISTINCT one.question_id FROM log_table AS one WHERE one.date between
"2022-09-19" and "2022-09-19" AND one.user_id = two.user_id ), 0, 1 )) AS num
FROM log_table AS two WHERE two.date = "2022-09-20" GROUP BY two.user_id ) info
WHERE info.num >0) as d2 on d5.user_id = d2.user_id left join (SELECT
info.user_id FROM ( SELECT two.user_id, sum( IF ( two.question_id IN ( SELECT
DISTINCT one.question_id FROM log_table AS one WHERE one.date between
"2022-09-18" and "2022-09-18" AND one.user_id = two.user_id ), 0, 1 )) AS num
FROM log_table AS two WHERE two.date = "2022-09-19" GROUP BY two.user_id ) info
WHERE info.num >0) as d1 on d5.user_id = d1.user_id

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