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<>经过一番探索和学习,明白了静态数码管的点亮原理。下面分享我的学习历程。
*
原理图说明
在51单片机的电路图中,有p20、p21、p22、p23的使能端,就是相当于4个开关。
P0口有8个端子分别为数码管的八段led, 也就是说控制使能端,可以控制这八个端子,不同的led亮则对应不同的数字或者是字母。
在单片机中,数码管的输出p0~p8,对应下图的P0端。
*
效果图显示
这里我令p20、p21、p22为高电平1、p23为低电平为0,即让最右边的数码管使能可以使用,显示的数字可定义一个数组存放1~9、a、b、c
、e、f。不同的单片机所使用的数码管不同(我这里的共阳极的数码管)
*
开源代码
//头文件 #include<reg51.h> //定义数组 typedef unsigned char u16; typedef unsigned int
u18; //单片机的管脚,分别连着对应的数码管 sbit p20=P2^0; sbit p21=P2^1; sbit p22=P2^2; sbit p23=
P2^3; //共阳数码管编码表 u16 code smaguan[16] ={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,
0x80,0x90,0x88,0x83, 0xc6,0xa1,0x86,0x8e}; //主程序 void main() { p20=1; //数码管不亮
p21=1; //数码管不亮 p22=1; //数码管不亮 p23=0; //数码管亮 P0=smaguan[15]; //p23对应数码管显示字母"F"
,共阳数码管编码表中可查 while(1); }