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<>一、题目描述
商人经营一家店铺，有number种商品，由于仓库限制每件商品的最大持有数量是item[index]，每种商品的价格在每天是
item_price[item_index][day]，通过对商品的买进和卖出获取利润，请给出商人在days天内能获取到的最大利润。
注：同一件商品可以反复买进和卖出；
<>二、输入描述
3 //输入商品的数量 number
3 // 输入商人售货天数 days
4 5 6 //输入仓库限制每件商品的最大持有数量是itemlindex]
1 2 3 // 输入第一件商品每天的价格
4 3 2 // 输入第二件商品每天的价格
1 5 3 // 输入第三件商品每天的价格
<>三、输出描述
32//输出商人在这段时间内的最大利润
<>四、解题思路
* 首先读取输入的商品数量 number 和商人售货天数 days；
* 使用 nextLine() 方法读取每件商品的最大持有数量 item[index]，并将其存储在字符串 str 中；
* 使用空格分隔字符串 str，将每件商品的最大持有数量转换为整数类型，并存储在数组 arr 中；
* 初始化变量 sum 为 0，用于存储总利润；
* 使用循环从 0 到 number-1，依次处理每件商品的价格：
* 使用 nextL
