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今天在编写cuda程序时，遇到一个很奇怪的问题, 就是在调用核函数时，返回cuda错误信息，报invalid argument 。
cudaError_t error = cudaGetLastError(); printf("CUDA error: %s\n",
cudaGetErrorString(error));
一般的理解是参数异常，有可能是参数过大，一种是非法参数。经过检查，参数传递错误基本排除。
最搞笑的是，我把核函数内部代码注释掉，参数为空，结果竟然还会报这个错！
__global__ void test() { const int tid = blockIdx.x; //printf("(tid: %d)",
tid); }
于是我猜想可能是之前存储分配的时候出现问题，经过检查，果不其然，找到一个二阶地址从Host到Device传递时出现的错误。
由于cuda在申请显存的过程中是手动完成的，地址赋值如果出现错误，其实是不会报错，因为计算机并不知道你的地址赋值出现错误。但是当开辟显存空间的时候，就会出现问题，导致cuda错误列表会记录，并且之后所有的计算全部会出现错误。
当出现该问题时，我的一个解决方法是，在每一次申请显存空间的时候，都使用代码cudaError_t来返回一下错误，如下：
cudaMalloc(**1**); cudaMemcpy(**1**, cudaMemcpyHostToDevice); cudaError_t
error = cudaGetLastError(); printf("CUDA error: %s\n",
cudaGetErrorString(error)); cudaMalloc(**2**); cudaMemcpy(**2**,
cudaMemcpyHostToDevice); cudaError_t error = cudaGetLastError(); printf("CUDA
error: %s\n", cudaGetErrorString(error)); cudaMalloc(**3**); cudaMemcpy(**3**,
cudaMemcpyHostToDevice); cudaError_t error = cudaGetLastError(); printf("CUDA
error: %s\n", cudaGetErrorString(error));
当在那个位置出现cuda的报错信息，那么就直接找出错位置之前的显存申请代码就可以了。
