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<>案例一：
#include "stdio.h" void main() { int x,y,z; x=1,y=1; z=x++,y++,++y; //逗号表达式
printf("%d,%d,%d\n",x,y,z); }
你觉得这个z值是多少呢？
分析：这个x++, y++, ++y 这是个逗号表达式，运算顺序自左至右，那有人要说了，简单，z = 2，
那我可要告诉你：错误；为啥错了？因为本例中z=x++含有赋值运算符，其优先级高于逗号逗号运算符，也即相当于这样 (z=x++),y++,++y;
运行结果：
解析：首先执行（z=x++） => z=1, x=2
然后继续执行y++, ++y => y=3
**此时若再次变化成这样：** z= (x++,y++,++y); //此时逗号表达式整体加了括号 printf("%d,%d,%d\n",x,y,z);
此时运行结果：
<>案例二：
void main() { int t; printf("t=%d\n",(t=1,t+5,t++)); }
自己分析一把，答案是1！
有人说，我认为是6，自左至右计算后的t是6！
是吗？ => 错误；
原因：逗号表达式中的t+5并不会影响t的值啊！
经过t=1，t+5后t的值仍然是1，经历t++时，注意此时是先赋值，然后再自增，所以逗号表达式的值是1；
运行结果：
**
<>案例三：
**
void main(){ int a,b; b=(a=1,a+1,a++); printf("b= %d\n",b); }
和案例二差不多，自己分析一把，在评论区可写下自己的解题过程，答案是1。
<>最后总结一下：
1. 逗号表达式结构：
表达式1，表达式2，表达式3，… ，表达式n
2. 逗号表达式的要领:
(1) 逗号表达式的运算过程为:【从左往右】逐个计算表达式。
(2) 逗号表达式作为一个整体，【它的值】为最后一个表达式(也即表达式n)的值。
(3) 逗号运算符的优先级别在所有运算符中最低。
(4)往往将逗号表达式与赋值运算符结合起来考查！
