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<>问题
java 统计字符串中每个字符出现的次数
实现方式：字符串基本操作
代码如下：
1、方法一:字符串的原始操作
public static void main(String [] sgrs){ /** *
如:"1王235868asda17394利3@@89我0我2342";统计出每个字符出现的次数。 */ String str=
"1王235868asda17394利3@@89我0我2342"; int[] count=new int[str.length()];//每个字符出现的次数
String b=new String();//存储去除重复之后的字符串 for(int i=0;i<str.length();i++){ if(!b.
contains(String.valueOf(str.charAt(i)))){ b+=String.valueOf(str.charAt(i)); }
else{ for(int j=0;j<b.length();j++){ if(str.charAt(i)==b.charAt(j)){ count[j]++;
} } } } System.out.println("原字符串str:"); System.out.println(str);
//System.out.println(b); for(int i=0;i<b.length();i++){ System.out.println(b.
charAt(i)+":出现的次数："+(count[i]+1)); } }
运行结果：
2、方式二、利用Map数据结构
public static void main(String[] args) { /** *
如:"1王235868asda17394利3@@89我0我2342";统计出每个字符出现的次数。 */ String str =
"1王235868asda17394利3@@89我0我2342"; char[] chars = str.toCharArray(); Map<
Character, Integer> map = new HashMap(); for (char c : chars) { if (map.
containsKey(c)) { map.put(c, map.get(c) + 1); }else{ map.put(c,1); } } for (Map.
Entry<Character, Integer> entry : map.entrySet()) { System.out.println("字符（"+
entry.getKey()+"）出现的次数为："+entry.getValue()); } }
运行结果：
注：如果要按照字符出现次数排序，也可以使用TreeMap
