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<>猜数字游戏
问题描述：在1—100的范围内，进行猜数字，共有8次机会。
键入1—100之间的整数，回车看结果。根据提示，进一步猜测。
解答：代码示例：
#猜数字游戏 import random #生成随机数 secret=random.randint(1,100) print(
"猜数字游戏！1—100的整数，你最多可以猜8次") tries=1 while tries<=8: guess=int(input(
"1-100的整数,第%d次猜,请输入:"%(tries))) if guess==secret: print("恭喜答对了!你只猜了%d次! \n
就是这个:%d!"%(tries,secret)) break elif guess>secret: print("不好意思,你的数大了一点!") tries
+= 1 else: print("不好意思,你的数小了一点!") tries += 1 else: print("哎呀!怎么还没猜中!再见咯!")
运行示例：
##拓展： random（）生成不同数字类型的用法
random.random() 用于生成一个随机浮点数：range[0.0,1.0)
random.uniform(a,b)
用于生成一个指定范围内的随机浮点数，a,b为上下限，只要a!=b,就会生成介于两者之间的一个浮点数，若a=b，则生成的浮点数就是a
random.randint(a,b) 用于生成一个指定范围内的整数，a为下限，b为上限，生成的随机整数a<=n<=b;若a=b，则n=a；若a>b，报错
random.randrange([start], stop [,step]) 从指定范围内，按指定基数递增的集合中获取一个随机数，基数缺省值为1
random.choice(sequence)
从序列中获取一个随机元素，参数sequence表示一个有序类型，并不是一种特定类型，泛指list，tuple，字符串等
random.shuffle(x[,random]) 用于将一个列表中的元素打乱
random.sample(sequence,k) 从指定序列中随机获取k个元素作为一个片段返回，sample函数不会修改原有序列
