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首先我们使用常规做法，循环交换完成。
lst = [1, 3, 5, 8] for i in range(0, len(lst)): lst[i], lst[0] = lst[0], lst[i]
for j in range(1, len(lst)): lst[j], lst[1] = lst[1], lst[j] for h in range(2,
len(lst)): lst[h], lst[2] = lst[2], lst[h] print(lst) lst[h], lst[2] = lst[2],
lst[h] lst[j], lst[1] = lst[1], lst[j] lst[i], lst[0] = lst[0], lst[i]
如果列表较长，元素较多，以上常规方法实现起来就比较吃力了，以下我们采用递归方式实现。
def permutations(position): if position == len(lst) - 1: print(lst) else: for
indexin range(position, len(lst)): lst[index], lst[position] = lst[position],
lst[index] permutations(position+1) lst[index], lst[position] = lst[position],
lst[index] permutations(0)
