[{"createTime":1735734952000,"id":1,"img":"hwy_ms_500_252.jpeg","link":"https://activity.huaweicloud.com/cps.html?fromacct=261f35b6-af54-4511-a2ca-910fa15905d1&utm_source=V1g3MDY4NTY=&utm_medium=cps&utm_campaign=201905","name":"华为云秒杀","status":9,"txt":"华为云38元秒杀","type":1,"updateTime":1735747411000,"userId":3},{"createTime":1736173885000,"id":2,"img":"txy_480_300.png","link":"https://cloud.tencent.com/act/cps/redirect?redirect=1077&cps_key=edb15096bfff75effaaa8c8bb66138bd&from=console","name":"腾讯云秒杀","status":9,"txt":"腾讯云限量秒杀","type":1,"updateTime":1736173885000,"userId":3},{"createTime":1736177492000,"id":3,"img":"aly_251_140.png","link":"https://www.aliyun.com/minisite/goods?userCode=pwp8kmv3","memo":"","name":"阿里云","status":9,"txt":"阿里云2折起","type":1,"updateTime":1736177492000,"userId":3},{"createTime":1735660800000,"id":4,"img":"vultr_560_300.png","link":"https://www.vultr.com/?ref=9603742-8H","name":"Vultr","status":9,"txt":"Vultr送$100","type":1,"updateTime":1735660800000,"userId":3},{"createTime":1735660800000,"id":5,"img":"jdy_663_320.jpg","link":"https://3.cn/2ay1-e5t","name":"京东云","status":9,"txt":"京东云特惠专区","type":1,"updateTime":1735660800000,"userId":3},{"createTime":1735660800000,"id":6,"img":"new_ads.png","link":"https://www.iodraw.com/ads","name":"发布广告","status":9,"txt":"发布广告","type":1,"updateTime":1735660800000,"userId":3},{"createTime":1735660800000,"id":7,"img":"yun_910_50.png","link":"https://activity.huaweicloud.com/discount_area_v5/index.html?fromacct=261f35b6-af54-4511-a2ca-910fa15905d1&utm_source=aXhpYW95YW5nOA===&utm_medium=cps&utm_campaign=201905","name":"底部","status":9,"txt":"高性能云服务器2折起","type":2,"updateTime":1735660800000,"userId":3}]
题目描述
蛇形矩阵是由1开始的自然数依次排列成的一个矩阵上三角形。
输入
本题有多组数据，每组数据由一个正整数N组成。（N不大于100）
输出
对于每一组数据，输出一个N行的蛇形矩阵。两组输出之间不要额外的空行。矩阵三角中同一行的数字用一个空格分开。行尾不要多余的空格。
样例输入
5
样例输出
1 3 6 10 15 2 5 9 14 4 8 13 7 12 11
我们从二维数组的方式看这个矩阵：（找规律）
为了实现这个读入方法，我们发现每次读入的数组之间存在一定的关系：
在第一次的双层循环中，是为了实现这个二维数组。
再下一次的双层循环中，是为了输出这个倒三角
public static void main(String[] args) { int[][] arr = new int[100][100];
Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int k = 1; for (int
i = 1; i <= n; i++) { for (int j = 0; j < i; j++) { arr[i-1-j][j] = k; k++; } }
int t = 0; for (int i = 0; i < n; i++, t++) { for (int j = 0; j < n-t; j++) {
System.out.print(arr[i][j] + " "); if(i + j == n - 1) { System.out.println(); }
} } }
输出结果：
