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第1关：将一个数组中的值按逆序重新存放
任务描述
本关任务：输入一批整数，最多100个，存入数组，将此数组中的值按逆序重新存放输出，例如，原来顺序为：8，6，5，4，1。要求改为：1，4，5，6，8。
测试说明
平台会对你编写的代码进行测试：
输入
第一行为n，表示输入数组a的n个整数。
第二行为输入的n个整数。
输出
输出逆置后的数组
测试输入：
10
91 1 42 32 9 57 6 33 2 88
预期输出：
88 2 33 6 57 9 32 42 1 91
#include<stdio.h> #define N 100 int main() { int a[100]; int m; int i = 0, n =
0, temp; scanf("%d",&n); for(i=0;i<n;i++) scanf("%d",&a[i]); for(i=0;i<n/2;i++){
temp= a[n-1-i]; a[n-1-i]=a[i]; a[i] = temp; } for(i=0;i<n;i++) printf("%d ", a[
i]); return 0; }
······通关成功······
如有问题，敬请斧正。
