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本题要求编写程序，将给定的n个整数存入数组中，将数组中的这n个数逆序存放，再按顺序输出数组中的元素。
输入格式:
输入在第一行中给出一个正整数n（1≤n≤10）。第二行输入n个整数，用空格分开。
输出格式:
在一行中输出这n个整数的处理结果，相邻数字中间用一个空格分开，行末不得有多余空格。
输入样例:
4 10 8 1 2
输出样例:
2 1 8 10 #include <stdio.h> int main(){ int n; scanf("%d", &n); int num[n];
for( int i=0; i<n; i++ ) scanf(" %d", &num[i]); Reverse( num, n ); for( int
j=0; j<n-1; j++ ) // 输出前n-1个数 printf("%d ", num[j]); printf("%d", num[n-1]); //
输出最后一个数，避免最后有空格 return 0; } void Reverse( int num[], int n ){ int mid = n / 2;
for( int i=0; i<mid; i++ ) swap( &num[i], &num[n-i-1] ); } void swap( int
*num1, int *num2 ){ int temp = *num1; *num1 = *num2; *num2 = temp; }
