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输入n个整数,存入数组a中(例如5、9、3、8),将数组a中n个数逆序存放(例如8、3、9、5),并输出数组中的n个元素。
思路很简单 第一个数和倒数第一个数交换 第二个数和倒数第二个数交换 以此类推
#include<stdio.h> int main() { int i=0,j=0,k; int a[99]; char ch;
while (1)//读入数据,正序储存 { scanf("%d",&a[i++]);
ch=getchar(); if (ch=='\n') { break;
} } for ( j = 0; j<i/2; j++)//将已有的数组倒过来,逆序储存 {
k=a[j]; a[j]=a[i-j-1]; a[i-j-1]=k; }
for (j = 0; j<i; j++)//输出逆序储存好的数组 { printf("%d ",a[j]); }
return 0; }