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A. 实验5-4 输出每个月的天数 题目描述
本题要求实现一个简单函数，能计算给定的年份和月份的天数。使得可以利用该函数，输出给定年份中每个月的天数。其中1、3、5、7、8、10、12月有31天，4、6、9、11月有30天，2月平年有28天，闰年有29天。
要求定义并调用函数month_days(year，month)，该函数返回year年month月的天数。 输入 年year 输出 该年1~12月每个月的天数
样例查看模式 正常显示 查看格式 输入样例1 2000 输出样例1 31 29 31 30 31 30 31 31 30 31 30 31
这道题没什么好说的
就是使用全局变量把函数的所有月份返回值记录并输出
int m1,m2,m3,m4,m5,m6,m7,m8,m9,m10,m11,m12; int year_(int y) {
if(y%4==0&&y%100!=0||y%400==0) return 1; else return 0; } void month_days(int
year) { if(year_(year)==1) {
m1=31;m2=29;m3=31;m4=30;m5=31;m6=30;m7=31;m8=31;m9=30;m10=31;m11=30;m12=31; }
else {
m1=31;m2=28;m3=31;m4=30;m5=31;m6=30;m7=31;m8=31;m9=30;m10=31;m11=30;m12=31; } }
#include<stdio.h> int main() { int year; scanf("%d",&year); month_days(year);
printf("%d %d %d %d %d %d %d %d %d %d %d
%d",m1,m2,m3,m4,m5,m6,m7,m8,m9,m10,m11,m12); return 0; }
