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【问题描述】
设一顺序表有若干元素,编写程序实现删除表中值重复的元素,即重复元素只保留一个。
【输入形式】
第一行输入一个N(N不大于100),表示顺序表的长度;
第二行输入N个整数,表示顺序表元素;
【输出形式】
输出去重后的顺序表。
【样例输入】
7
2 2 2 3 3 2 2
【样例输出】
2 3
初始化并创立一个顺序表
typedef struct list{ //定义顺序表 int *data; int len; int size; }list,*Plist; int
init_list(Plist L){ //初始化顺序表 L->data=(int *)malloc(sizeof(int)*SIZE);
L->size=SIZE; L->len=0; return 1; } int creat_list(Plist L,int n){ //创建顺序表 int
i; if(L->len==L->size){ L->data=(int
*)realloc(L->data,(L->size+INCREAM)*sizeof(int)); L->size+=INCREAM; }
for(i=0;i<n;i++){ scanf("%d",&L->data[i]); L->len++; } return 1; }
删除重复值的具体算法
int delete_same_