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题目：
使用函数求特殊a串数列和。 给定两个均不超过9的正整数a和n，要求编写函数fn(a,n)
求a+aa+aaa++⋯+aa⋯aa(n个a）之和，fn须返回的是数列和
思路：
1、先输入a,n的值
2、编写函数，使用for循环再（0，n）之间遍历，构造加数。
3、再对加数相加求和。
代码：
a = int(input("请输入数字个位数上的数字:")) b = int(input("请输入您最后要加到的数字位数（要求：不超过9的正整数）:"))
def add(m, n): r = 0 result=0 for i in range(0, n): r += m * 10 ** i
print(r,end=",") result += r return result print("相加之后的结果为=",add(a, b))
结果：
请输入数字个位数上的数字:3 请输入您最后要加到的数字位数（要求：不超过9的正整数）:4 3,33,333,3333,相加之后的结果为= 3702
但是有个小问题：就是如何去掉最后一个逗号或者加号？如果有大佬会的话请在评论下留言。万分感激
