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1、数组对象的合并去重
方法一、推荐使用
1)、封装
/* *数组对象去重 */ export function removedup(arr, batch) { if (!Array.isArray(arr))
{ return arr; } if (arr.length == 0) { return []; } let obj = {}; let uniqueArr
= arr.reduce(function (total, item) { obj[item[batch]] ? '' : (obj[item[batch]]
= true && total.push(item)); return total; }, []); return uniqueArr; }
2)、引用
import { removedup } from ......
// arrObjList 需要去重的数组对象, score 根据这个属性进行去重
let uniqueArrObjList = removedup(arrObjList, "score");
方法二、
<script> let json1=[ {id:1,name:"aaa"}, {id:2,name:"bbb"}, {id:3,name:"ccc"},
] let json2=[ {id:1,name:"aaa"}, {id:2,name:"bbb"}, {id:4,name:"ddd"}, ] let
json = json1.concat(json2); //两个数组对象合并 let newJson = []; //盛放去重后数据的新数组
for(item1 of json){ //循环json数组对象的内容 let flag = true; //建立标记,判断数据是否重复,true为不重复
for(item2 of newJson){ //循环新数组的内容 if(item1.id==item2.id){
//让json数组对象的内容与新数组的内容作比较,相同的话,改变标记为false flag = false; } } if(flag){ //判断是否重复
newJson.push(item1); //不重复的放入新数组。 新数组的内容会继续进行上边的循环。 } }
console.log("newJson",newJson); </script>
1、数组的合并去重:
<script> let arr1 = [3,5,2,3,6]; let arr2 = [5,2,4,6,8,7,9,2]; let arr =
arr1.concat(arr2); //合并数组 let arrNew= new Set(arr); //通过set集合去重
console.log("arrNew",Array.from(arrNew)); //将set集合转化为数组 </script>