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<>兑换了一个力扣鼠标垫
说来也算是无心插柳，自己作为半个转行仔，一开始压根不知道什么 leetcode
。工作会在网上了解到算法数据结构的重要性，才慢慢的进入力扣开始做题。也没有具体的学习规划，只时不时做几题玩玩。时间久了积分就上去了(当然水平依旧很普通)。再后来知道积分可以兑换东西，现在刚需一个鼠标垫就顺手兑换了。
<>谈一下对算法和数据结构的看法
作为一个普通的java web仔，从java
web这个方向来讲的话，我觉得懂得常见的一些算法数据结构就差不多了。平时也还是以完成业务功能，解决工作中的实际问题为主。不过多做做题锻炼锻炼脑子也不错，编程能力也确实会有所提升。
事实上我遇到笔试或者做力扣每日一题经常有不会做的情况，感觉也不用太在意，其实这和八股文一样，除了证明你最近背过这个东西外，也没啥其他的意义。
但是现在行业的人太多了，招聘要求越来越高，对于稍微好点的公司，如果没有和公司匹配或者比较不错的项目经历，其他方面也没啥亮点，那算法也许就是最后一根救命稻草了。
<>最后分享一下我开始做力扣题时印象最深的一道题。
力扣第五题: 最长回文子串，因为当时一开始做了几道题，各种不会，想放弃了。直到做出了这题，
比一些优秀题解还快点，才有了兴趣坚持下来。
class Solution { char[] chs; int skipSize = 0; int resSize = 0; String res = ""
; public String longestPalindrome(String s) { chs = s.toCharArray(); for (int i
= 0; i < chs.length; i++) { matchLeftAndRight(i); //跳过右侧相同字符 i += skipSize; }
return res; } private void matchLeftAndRight(int idx) { int leftIdx = idx - 1;
int rightIdx = idx + 1; //如果右边有相同的字符,右移 while (rightIdx < chs.length && chs[
rightIdx] == chs[idx]) { rightIdx++; } //记录跳过相同的字符的个数 skipSize = rightIdx - idx
- 1; while (leftIdx >= 0 && rightIdx < chs.length && chs[leftIdx] == chs[
rightIdx]) { leftIdx--; rightIdx++; } leftIdx++; rightIdx--; int cuStrSize =
rightIdx- leftIdx + 1; if (cuStrSize <= resSize) { return; } resSize = cuStrSize
; res = new String(chs, leftIdx, cuStrSize); } }
