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刷Python小屋的时候连续遇到五六道题关于——求array类型二维数组下元素中数值等于特定值的整数之和,这类的问题,整理一下。
传统方法:用for循环来遍历,使用if取特定值
但是这样效率比较低,(Python小屋的题目里不让用for循环),所以本文使用array类型的简便方法。
原理:
#arr为一个array类型的数组 def f(arr): return arr%3==0 flag=f(arr) print(flag)
print(arr[f]) #如果flag相同位置上为True,返回arr上元素的值,返回的array形状为(m,1)
1.求array类型中所有偶数之和
import numpy as np def func(arr): return sum(arr[arr%2==0])
2. 求array类型中所有大于20的偶数之和
def func(arr): arr1=arr[arr>20] return arr1[arr1%2==0]
3.返回array数组中所有能被2整除或者被7整除的整数之和
def func(arr):#默认arr是一个整数数组 p1=arr%2==0 p2=arr%7==0 return arr[p1+p2]
4.返回array类型中下标为col的元素中数值为value的那些行的整数之和
def func(arr,col,value): flag=arr[:,col,col+1]==value flag=flag.flatten()
return sum(sum(arr[flag,:]))