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<>一、问题再现
table组件使用row-class-name属性无效!
<template> <div> <h3>Table表格组件的使用</h3> <el-table :data="tableData" stripe
border :row-class-name="tableRowClassName"> <el-table-column prop="id" label="编号
" width="200"></el-table-column> <el-table-column prop="name" label="姓名"></
el-table-column> <el-table-column prop="age" label="年龄"></el-table-column> <
el-table-column prop="email" label="邮箱"></el-table-column> </el-table> </div> </
template> <script> export default { name: "Table", data(){ return { tableData: [
{id:1101,name:'小张',age:22,email: '[email protected]'}, {id:1102,name:'小王',age:25,
email: '[email protected]'} ] } }, methods: { tableRowClassName({row, rowIndex})
{ /*console.log('row的值：'+ row); console.log('rowIndex的值：' + rowIndex);*/ if (
rowIndex=== 0) { return 'warning-row'; } else if (rowIndex === 1) { return
'success-row'; } return ''; } }, } </script> <style scoped> .el-table
.warning-row { background: oldlace; } .el-table .success-row { background:
#f0f9eb; } </style>
<>二、解决方案
<>1、网上大佬提供的解决方案
根据这位大佬的思路，于是我把stripe属性删除，只保留:row-class-name属性，但是依然无效！
<>2、自己的解决方案
我把官方案例完整的复制到自己的页面中发现row-class-name属性是可以生效的，经过仔细对比，只有在style样式中的scoped属性存在差异，其他没有差别。
解决方法：把当前组件中style的scoped属性删除即可。
如果某一行的row-class-name没有生效，可能是stripe和row-class-name属性冲突导致的，此时可以把stripe属性删除即可！
