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下列给定函数中，函数fun的功能是：统计字符串中各元音字母(即A，E，I，O，U)的个数。注意：字母不分大小写。例如，输入THIs is a
boot，则应输出是1 0 2 2 0。
请改正程序中的错误，使它能得出正确的结果。
注意：不要改动main函数，不得增行或删行，也不得更改程序的结构。
试题程序：
#include
#include
#include
/*************found**************/
fun(char *s, int num[5])
{ int k, i=5;
for(k=0;k
/*************found**************/
num[i]=0;
for(;*s;s++)
{ i=-1;
/*************found**************/
switch(s)
{ case 'a': case'A':{i=0;break;}
case 'e ': case 'E':{i=1;break;}
case 'i': case 'I':{i=2;break;}
case 'o': case 'O':{i=3;break;}
case 'u': case 'U':{i=4;break;}
}
if(i>=0)
num[i]++;
}
}
void main()
{ char s1[81]; int num1[5], i;
system("CLS");
printf("\nPlease enter a string: ");
gets(s1);
fun(s1, num1);
for(i=0;i<5;i++) printf("%d ",num1[i]);
printf("\n");
}
(1)错误：fun(char *s, int num[5])
(2)错误：num[i]=0;
(3)错误：switch(s) 正确：void fun(char *s, int num[5]) 正确：num[k]=0; 正确：switch(*s)
