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题目：
两个乒乓球队进行比赛，各出三人。甲队为a,b,c三人，乙队为x,y,z三人。已抽签决定
比赛名单。有人向队员打听比赛的名单。a说他不和x比，c说他不和x,z比，请编程序找出
三队赛手的名单。
思路：
循环依次比较，两两比较，判断参赛队员是否重复，因此需要两个if 在循环中间判断
代码实现：
//两个乒乓球队进行比赛，各出3人。甲队为A,B,C 3人，乙队为X,Y,Z 3人
//以抽签决定比赛名单。有人向队员打听比赛名单，A说他不和X比，C说他不和X,Z比 //请编程序找出3对赛手名单 int main() { int a, b,
c; //a是A的对手 b是B的对手 c是C的对手 for (a = 'X'; a <= 'Z'; a++) { for (b = 'X'; b <=
'Z'; b++) { if (a != b)//避免重复比赛 { for (c = 'X'; c <= 'Z'; c++) { if (a !=
c&&b!=c)//避免重复比赛 { if (a != 'X' && c != 'X' && c != 'Z') { printf(" A对%c\n
B对%c\n C对%c", a, b, c); } } } } } } return 0; }
输出结果：
感谢观看，如果有帮忙，麻烦点个赞，谢谢！
