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使用循环遍历求出数组中的最大值和最小值: package com.666.test3; import java.util.Scanner; /** *
@unthor : YSH * @date : 9:37 2022/4/15 */ public class Test2 { public static
void main(String[] args) { //定义输入工具类 Scanner sc = new Scanner(System.in);
//定义一个长度为5的整形数组，储存学生的成绩，遍历数组求出最大值和最小值 int[] numsAry = new int[5]; for (int
i=0;i<numsAry.length;i++){ System.out.println("请输入第"+(i+1)+"个同学成绩:");
numsAry[i]=sc.nextInt(); } //遍历输入的分数 for(int n : numsAry){
System.out.print(n+"\t"); } System.out.println(" "); //求数组中的最大值和最小值 int
max=numsAry[0];//定义数组0位置上的分数，作为初始的最大值 int min=numsAry[0];//定义数组0位置上的分数，作为初始的最小值
//遍历循环进行比较 for (int i=1;i<numsAry.length;i++){ //当前最大值小于遍历到的数组元素时，将数组元素存储到max中
if (max<numsAry[i]){ max=numsAry[i]; } //当前最小值大于遍历到的数组元素时，将数组元素存储到min中 if
(min>numsAry[i]){ min=numsAry[i]; } }
System.out.println("最大值为:"+max+"最小值为:"+min); } }
代码运行结果:
