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在对文件进行操作时,某些时候需要获取当前文件夹下所有文件的文件名,如获取“E:\工作表格\数据统计\网站日志\日志”,这个目录下所有文件的名字
在Windows系统命令行窗口下,查看当前文件夹下的所有文件名会用到dir,因此在代码中需要用到os模块
代码实现
# 导入os模块 import os # path定义要获取的文件名称的目录 path = "E:\工作表格\数据统计\网站日志\日志" #
os.listdir()方法获取文件夹名字,返回数组 file_name_list = os.listdir(path) # 转为转为字符串
file_name = str(file_name_list) # replace替换"["、"]"、" "、"'" file_name =
file_name.replace("[", "").replace("]", "").replace("'", "").replace(",",
"\n").replace(" ", "") # 创建并打开文件list.txt f = open(path + "\\" + "文件list.txt",
"a") # 将文件下名称写入到"文件list.txt" f.write(file_name)
输出结果