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<>生成随机数
题目：
生成100个1到6的随机整数，统计1~6每个数字出现的概率
方法一：
使用java.util.Math
Math类中有一个静态方法：random()，生成double类型的随机数（范围：[0.0~1.0) 不包括1）
Modifier and TypeMethodDescription
static doublerandom()生成double类型的随机数（范围：[0.0~1.0) 不包括1）
如何生成1~6的随机整数？
int x=(int)(Math.random()*6+1); Math.random()*6 范围是 [0.0-6.0) 不包括6 Math.random(
)*6+1 范围是[1.0-7.0) 不包括7 但是有强制类型转换double-->int，所以6.7会被转换成6
代码：
public class CreatRandom1 { public static void main(String[] args) { int[] arr1
=new int[100]; int[] arr2=new int[7]; for (int i = 0; i < arr1.length; i++) {
arr1[i]=(int)(Math.random()*6+1); arr2[arr1[i]]++; } for (int j = 1; j < arr2.
length; j++) { System.out.println(j+"数字出现了:"+arr2[j]+"次"); } } }
方法二：
使用java.util.Random
Random类中一个方法 nextInt(int bound)，生成0.0到指定范围的随机整数
Modifier and TypeMethodDescription
intnextInt(int bound)生成随机整数（范围：[0.0~bound) 不包括bound）
如何生成1~6的随机整数？
Random random=new Random(); int x=random.nextInt(6)+1; random.nextInt(6) 范围：[
0.0-6.0) 不包括6 random.nextInt(6)+1 范围：[1.0-7.0)不包括7，int类型，像6.6这样的数就是6. 其他代码同上
<>如何产生其他类型的随机数，请看另一篇文章java.util.Random.
