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小东所在公司要发年终奖，而小东恰好获得了最高福利，他要在公司年会上参与一个抽奖游戏，游戏在一个6*6的棋盘上进行，上面放着36个价值不等的礼物，每个小的棋盘上面放置着一个礼物，他需要从左上角开始游戏，每次只能向下或者向右移动一步，到达右下角停止，一路上的格子里的礼物小东都能拿到，
请设计一个算法使小东拿到价值最高的礼物。
给定一个6*6的矩阵board，其中每个元素为对应格子的礼物价值,左上角为[0,0],请返回能获得的最大价值，保证每个礼物价值大于100小于1000。
class Bonus { public: int getMost(vector<vector<int> > board) {
if(board.empty()) { return 0; } vector<vector<int>> a=board; for(int
i=1;i<a.size();i++) { a[i][0]=a[i-1][0]+a[i][0]; } for(int
i=1;i<a[0].size();i++) { a[0][i]=a[0][i-1]+a[0][i]; } for(int
i=1;i<a.size();i++) { for(int j=1;j<a[0].size();j++) { if(a[i-1][j]>a[i][j-1])
{ a[i][j]=a[i-1][j]+a[i][j]; } else { a[i][j]=a[i][j-1]+a[i][j]; } } } return
a[5][5]; } };
