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问题描述:
计算机2000年问题,又叫做“千年虫”、“电脑千禧年千年虫问题”或“千年危机”。缩写为“Y2K”。是指在某些使用了计算机程序的智能系统(包括计算机系统、自动控制芯片等)中,由于其中的年份只使用两位十进制数来表示,因此当系统进行(或涉及到)跨世纪的日期处理运
算时(如多个日期之间的计算或比较等),就会出现错误的结果,进而引发各种各样的系统功
能紊乱甚至崩溃。因此从根本上说千年虫是一种程序处理日期上的bug(计算机程序故障),而非病毒。
输入:
人员序列信息:【45,89,1998,00,75,33,1968,37,1958,90】
输出:
输出参考:【1933, 1937, 1945, 1958, 1968, 1975, 1989, 1990, 1998, 2000】
思路:先把两位数和四位数分开来看,当数为00时,我们将原来的值加上2000,就等于它真实的年份,再将剩下大于0小于100的两位数加上1900,再用列表对象的sort()方法。
a=[45,89,1998,00,75,33,1968,37,1958,90] for index,item in enumerate(a): if(item
==00): item+=2000 a[index]=item elif 0<item<100: item+=1900 a[index]=item else:
item=item a[index]=item for i in a: print(i) a.sort() print('升序排序',a)