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<>如何用python实现斐波那契数列的前100个
如何用python实现斐波那契数列的前100个
首先分析题目
实现斐波那契数列的前100个, 斐波那契数列是什么?
斐波那契数列(Fibonacci sequence),又称黄金分割数列、因数学家莱昂纳多·斐波那契(Leonardoda
Fibonacci)以兔子繁殖为例子而引入,故又称为“兔子数列”,指的是这样一个数列:**
<>0、1、1、2、3、5、8、13、21、34、……
*在数学上,斐波那契数列以如下被以递推的方法定义:F(0)=0,F(1)=1, F(n)=F(n - 1)+F(n - 2)(n ≥ 2,n ∈ N)
<>0,1,0+1,1+1,1+2,2+3,3+5,5+8,8+13,13+21……
采用for循环 之后会用到序列解包
0、1、 1、 2、 3、 5、 8、 13、 21、 34、……
0,1,0+1,1+1,1+2,2+3,3+5,5+8,8+13,13+21……
a、b、a+b
b的值给了a, a+b的值给了b 不断循环一直打印a
<>代码实现
a = 0
b = 1
for i in range(100):
print(a, end=’ ')
a, b = b, a+b
<>祝大家Python学习顺利!