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<>问题介绍
有时候我们需要将两个字典进行合并，我们需要相同的键的值，合并成一个列表。
<>代码
dic_a = {"key1":1,"key5":2} dic_b = {"key1":3,"key4":4} print("合并前的字典1是{}".
format(dic_a)) print("合并前的字典2是{}".format(dic_b)) # 实现的目标是 "key2":[2,3]
result_dic= {} ''' 核心思路： 1：遍历字典1和字典2的每一个键 2：如果两个字典的键是一样的，就给新字典的该键赋值为空列表
然后空列表依次添加字典1和字典2 的值，然后将最后的值赋值给原字典 3：如果两个字典的键不同，则分别将键值对加到新列表中 ''' for k,v in
dic_a.items(): for m,n in dic_b.items(): if k == m: result_dic[k] = []
result_dic[k].append(dic_a[k]) result_dic[k].append(dic_b[k]) dic_a[k] =
result_dic[k] dic_b[k] = result_dic[k] else: result_dic[k] = dic_a[k] result_dic
[m] = dic_b[m] # if k in dic_b.keys(): print("合并后的字典是{}.".format(result_dic))
<>结果
