[{"createTime":1735734952000,"id":1,"img":"hwy_ms_500_252.jpeg","link":"https://activity.huaweicloud.com/cps.html?fromacct=261f35b6-af54-4511-a2ca-910fa15905d1&utm_source=V1g3MDY4NTY=&utm_medium=cps&utm_campaign=201905","name":"华为云秒杀","status":9,"txt":"华为云38元秒杀","type":1,"updateTime":1735747411000,"userId":3},{"createTime":1736173885000,"id":2,"img":"txy_480_300.png","link":"https://cloud.tencent.com/act/cps/redirect?redirect=1077&cps_key=edb15096bfff75effaaa8c8bb66138bd&from=console","name":"腾讯云秒杀","status":9,"txt":"腾讯云限量秒杀","type":1,"updateTime":1736173885000,"userId":3},{"createTime":1736177492000,"id":3,"img":"aly_251_140.png","link":"https://www.aliyun.com/minisite/goods?userCode=pwp8kmv3","memo":"","name":"阿里云","status":9,"txt":"阿里云2折起","type":1,"updateTime":1736177492000,"userId":3},{"createTime":1735660800000,"id":4,"img":"vultr_560_300.png","link":"https://www.vultr.com/?ref=9603742-8H","name":"Vultr","status":9,"txt":"Vultr送$100","type":1,"updateTime":1735660800000,"userId":3},{"createTime":1735660800000,"id":5,"img":"jdy_663_320.jpg","link":"https://3.cn/2ay1-e5t","name":"京东云","status":9,"txt":"京东云特惠专区","type":1,"updateTime":1735660800000,"userId":3},{"createTime":1735660800000,"id":6,"img":"new_ads.png","link":"https://www.iodraw.com/ads","name":"发布广告","status":9,"txt":"发布广告","type":1,"updateTime":1735660800000,"userId":3},{"createTime":1735660800000,"id":7,"img":"yun_910_50.png","link":"https://activity.huaweicloud.com/discount_area_v5/index.html?fromacct=261f35b6-af54-4511-a2ca-910fa15905d1&utm_source=aXhpYW95YW5nOA===&utm_medium=cps&utm_campaign=201905","name":"底部","status":9,"txt":"高性能云服务器2折起","type":2,"updateTime":1735660800000,"userId":3}]
1 map()函数的简介以及语法:
map是python内置函数,会根据提供的函数对指定的序列做映射。
map()函数的格式是:
map(function,iterable,...)
第一个参数接受一个函数名,后面的参数接受一个或多个可迭代的序列,返回的是一个集合。
把函数依次作用在list中的每一个元素上,得到一个新的list并返回。注意,map不改变原list,而是返回一个新list。
2 map()函数实例:
del square(x): return x ** 2 map(square,[1,2,3,4,5]) # 结果如下: [1,4,9,16,25]
通过使用lambda匿名函数的方法使用map()函数:
map(lambda x, y: x+y,[1,3,5,7,9],[2,4,6,8,10]) # 结果如下: [3,7,11,15,19]
通过lambda函数使返回值是一个元组:
map(lambdax, y : (x**y,x+y),[2,4,6],[3,2,1]) # 结果如下 [(8,5),(16,6),(6,7)]
当不传入function时,map()就等同于zip(),将多个列表相同位置的元素归并到一个元组:
map(None,[2,4,6],[3,2,1]) # 结果如下 [(2,3),(4,2),(6,1)]
通过map还可以实现类型转换
将元组转换为list:
map(int,(1,2,3)) # 结果如下: [1,2,3]
将字符串转换为list:
map(int,'1234') # 结果如下: [1,2,3,4]
提取字典中的key,并将结果放在一个list中:
map(int,{1:2,2:3,3:4}) # 结果如下 [1,2,3]