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下面这题你知道答案了吗？
假设现在我们定义一个列表a，内容如下：
a = [1,2,3,4,5,6,7,8,9,10]
学习过python基础的都知道，针对列表的操作，python提供了一些内置的函数，比如append、count、extend、pop、insert、remove、reverse等函数，那接下来大家先来一起看一段代码，大家觉得执行后的输出结果是啥呢？
a = [1,2,3,4,5,6,7,8,9,10] for i in a: a.remove(i) print(a)
remove是移除列表元素的方法，那么这段脚本执行后的最终结果是什么呢？
你的答案是否正确呢？
思考了片刻之后，那你是不是觉得，最后输出的是一个空的列表呢？
很显然，最终输出的答案肯定不是一个空的列表，最终输出的结果是：
[2, 4, 6, 8, 10]
是的，你没有看错，最后输出的是：[2, 4, 6, 8, 10]。
那为什么输出的空列表呢？因为在使用for i in a 这样的操作的时候，没遍历一次后，删除a列表中的一个元素后，a列表的值已经发生了变化。
代码运行的过程如下：
第一次循环，删除下标为0的元素后，此时，列表a变为了[2, 3, 4, 5, 6, 7, 8, 9, 10]
第二次循环，删除下表为1的元素，此时列表a中剔除的是元素3，列表a变为了[2, 4, 5, 6, 7, 8, 9, 10]，
以此类推，最后执行代码的输出结果是：[2, 4, 6, 8, 10]
怎么解决上述问题呢？
1、将列表a进行copy一份后进行循环遍历删除
for i in a.copy(): a.remove(i) print(a)
或者
for i in a[:]: a.remove(i) print(a)
2、将列表倒序后再遍历删除
for i in a[::-1]: a.remove(i) print(a)
除了遍历列表，在循环遍历其他类型数据的时候也要注意避免采这种坑，今天的分享就到这了，觉得小编写的对你有帮助的话，可以点个赞哟。
