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题目：有5个长度不一的数组a1、a2、a3、a4、a5，现各从数组中取出一个数，组成一个新的数组，要求从a1取出的数必须小于从a2取的数，同理从a2取出的数必须小于从a3取的数，以此类推，列出所有满足条件的数组。
题目挺简单，看一下就明白，然后第一时间用了一堆for循环，脚本如下：
a1 = [1,2,4] a2 = [2,3,4,5] a3 = [1,4,7] a4 = [3,6,7,8] a5 = [3,6,8,9,10] for i
in a1: for j in a2: for k in a3: for l in a4: for m in a5: if i<j<k<l<m: print(i
,j,k,l,m)
输出结果没错，但是看着这一堆for循环，总感觉很不爽，一番搜索后，发现了itertools.product(A,
B)这个函数，这个函数会返回A、B中的元素的笛卡尔积的元组，似乎满足条件，于是上面的脚本改成了下面的样子
import itertools for i in itertools.product(a1,a2,a3,a4,a5): if i[0]<i[1]<i[2]<
i[3]<i[4]: print(i)
